7n+2[3(1+n)-2(1+n)]=14

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Solution for 7n+2[3(1+n)-2(1+n)]=14 equation:


Simplifying
7n + 2[3(1 + n) + -2(1 + n)] = 14
7n + 2[(1 * 3 + n * 3) + -2(1 + n)] = 14
7n + 2[(3 + 3n) + -2(1 + n)] = 14
7n + 2[3 + 3n + (1 * -2 + n * -2)] = 14
7n + 2[3 + 3n + (-2 + -2n)] = 14

Reorder the terms:
7n + 2[3 + -2 + 3n + -2n] = 14

Combine like terms: 3 + -2 = 1
7n + 2[1 + 3n + -2n] = 14

Combine like terms: 3n + -2n = 1n
7n + 2[1 + 1n] = 14
7n + [1 * 2 + 1n * 2] = 14
7n + [2 + 2n] = 14

Reorder the terms:
2 + 7n + 2n = 14

Combine like terms: 7n + 2n = 9n
2 + 9n = 14

Solving
2 + 9n = 14

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 9n = 14 + -2

Combine like terms: 2 + -2 = 0
0 + 9n = 14 + -2
9n = 14 + -2

Combine like terms: 14 + -2 = 12
9n = 12

Divide each side by '9'.
n = 1.333333333

Simplifying
n = 1.333333333

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